Problem Archive

Consider all the triangles having:

There are nine such triangles having a perimeter $\le 50$.
Listed and shown in ascending order of their perimeter, they are:

$A(-4, 3)$, $B(5, 0)$, $C(4, -3)$
$A(4, 3)$, $B(5, 0)$, $C(-4, -3)$
$A(-3, 4)$, $B(5, 0)$, $C(3, -4)$


$A(3, 4)$, $B(5, 0)$, $C(-3, -4)$
$A(0, 5)$, $B(5, 0)$, $C(0, -5)$
$A(1, 8)$, $B(8, -1)$, $C(-4, -7)$


$A(8, 1)$, $B(1, -8)$, $C(-4, 7)$
$A(2, 9)$, $B(9, -2)$, $C(-6, -7)$
$A(9, 2)$, $B(2, -9)$, $C(-6, 7)$
0264_TriangleCentres.gif

The sum of their perimeters, rounded to four decimal places, is $291.0089$.

Find all such triangles with a perimeter $\le 10^5$.
Enter as your answer the sum of their perimeters rounded to four decimal places.

Solution
No solution yet. Write yours at solutions/s264.md.
Problems sourced from Project Euler · Non-commercial & educational use only · CC BY-NC-SA 4.0