Take the number $192$ and multiply it by each of $1$, $2$, and $3$:
$$\begin{align} 192 \times 1 &= 192\\ 192 \times 2 &= 384\\ 192 \times 3 &= 576 \end{align}$$By concatenating each product we get the $1$ to $9$ pandigital, $192384576$. We will call $192384576$ the concatenated product of $192$ and $(1,2,3)$.
The same can be achieved by starting with $9$ and multiplying by $1$, $2$, $3$, $4$, and $5$, giving the pandigital, $918273645$, which is the concatenated product of $9$ and $(1,2,3,4,5)$.
What is the largest $1$ to $9$ pandigital $9$-digit number that can be formed as the concatenated product of an integer with $(1,2, \dots, n)$ where $n \gt 1$?
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