Problem Archive

The series, $1^1 + 2^2 + 3^3 + \cdots + 10^{10} = 10405071317$.

Find the last ten digits of the series, $1^1 + 2^2 + 3^3 + \cdots + 1000^{1000}$.

Solution
No solution yet. Write yours at solutions/s48.md.
Problems sourced from Project Euler · Non-commercial & educational use only · CC BY-NC-SA 4.0